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Durables

Authors
Affiliations
Johns Hopkins University
Econ-ARK
Johns Hopkins University
Econ-ARK

A durable good is one that provides utility over multiple periods rather than being consumed immediately. The consumer’s goal is to

maxs=tTβstu(cs,ds)\max \sum_{s=t}^{T} \beta^{s-t} \uFunc(c_{s},d_{s})

where dsd_{s} is the stock of the durable good, and all other variables are as usually defined.

We will assume that the stock of the durable good evolves over time according to

dt+1=(1δ)dt+xt+1,d_{t+1} = (1-\delta)d_{t}+{x}_{t+1},

where xt{x}_{t} is period-t eXpenditure on the durable good and δ\delta is the durable good’s depreciation rate (a good with a lower value of δ\delta is said to be “more durable”). This geometric depreciation assumption contrasts with alternatives like “one-hoss-shay” depreciation, where each period there is some probability that the durable completely fails.

For simplicity, we abstract from asymmetries between buying and selling the durable good (there is no restriction requiring xt>0{x}_{t}>0).

The dynamic budget constraint subtracts expenditures on durables from available resources:

mt+1=(mtctxt)R+yt+1.{m}_{t+1} = ({m}_{t}-c_{t}-{x}_{t})\Rfree + y_{t+1}.

Bellman’s equation is

vt(mt,dt1)=max{ct,xt}[u(ct,dt)+βvt+1(mt+1,dt)],\vFunc_{t}({m}_{t},d_{t-1}) = \max_{\{c_{t},{x}_{t}\}} \left[\uFunc(c_{t},d_{t}) + \beta \vFunc_{t+1}({m}_{t+1},d_{t})\right],

where dt1d_{t-1} is the state variable because the level of durables in period tt is not determined until you choose spending on durables in that period. Equivalently, treating dtd_{t} directly as the control variable:

vt(mt,dt1)=max{ct,dt}[u(ct,dt)+βvt+1(mt+1,dt)],\vFunc_{t}({m}_{t},d_{t-1}) = \max_{\{c_{t},d_{t}\}} \left[\uFunc(c_{t},d_{t}) + \beta \vFunc_{t+1}({m}_{t+1},d_{t})\right],

subject to

mt+1=(mtct(dt(1δ)dt1)=xt)R+yt+1{m}_{t+1} = \left({m}_{t}-c_{t}-\overbrace{(d_{t}-(1-\delta)d_{t-1})}^{={x}_{t}}\right)\Rfree+y_{t+1}

or (substituting this into (5)),

vt(mt,dt1)=max{ct,dt}{u(ct,dt)+βvt+1((mtct(dt(1δ)dt1))R+yt+1,dt)}.\vFunc_{t}({m}_{t},d_{t-1}) = \max_{\{c_{t},d_{t}\}} \left\{\uFunc(c_{t},d_{t}) + \beta \vFunc_{t+1}(({m}_{t}-c_{t}-(d_{t}-(1-\delta)d_{t-1}))\Rfree+y_{t+1},d_{t})\right\}.

Since this equation has two control variables, ctc_{t} and dtd_{t}, there are two first order conditions:

wrt ctc_{t}:

utcRβvt+1m=0utc=Rβvt+1m\begin{aligned} \uFunc_{t}^{c} - \Rfree\beta \vFunc^{{m}}_{t+1}& = 0 \\ \uFunc_{t}^{c}& = \Rfree\beta \vFunc^{{m}}_{t+1} \end{aligned}

wrt dtd_{t}:

utd=β(Rvt+1mvt+1d)=Rβvt+1mβvt+1d.\uFunc_{t}^{d} = \beta(\Rfree \vFunc_{t+1}^{{m}} - \vFunc^{d}_{t+1}) = \Rfree\beta \vFunc_{t+1}^{{m}}-\beta \vFunc^{d}_{t+1}.

Note that when taking the derivative with respect to ctc_{t} you assume that dt/ct=0\partial d_{t}/\partial c_{t} = 0 and vice versa. Although the first order conditions will define a relationship between the optimal values of ctc_{t} and dtd_{t}, there is no mechanical link that applies at this point.

Now we want to apply the Envelope theorem. Basically, the Envelope theorem says that at the optimal levels of the control variables the partial derivative of the entire value function with respect to each control variable is zero. This means that when taking the derivative with respect to a state variable you can simply ignore all terms that involve ct/mt,dt/mt,ct/dt1,\partial c_{t}/ \partial {m}_{t}, \partial d_{t} / \partial {m}_{t}, \partial c_{t} / \partial d_{t-1}, and dt/dt1.\partial d_{t} / \partial d_{t-1}. So, for example, the full expression for the derivative of the value function with respect to mt{m}_{t} is:

vtm=u(ct,dt)ctctmt+u(ct,dt)dtdtmt+[mt+1mt+mt+1ctctmt+mt+1dtdtmt]βvt+1m+βvt+1ddtmt\begin{aligned} \vFunc_{t}^{{m}} & = \frac{\partial \uFunc(c_{t},d_{t})}{\partial c_{t}} \frac{\partial c_{t}}{\partial {m}_{t}} + \frac{\partial \uFunc(c_{t},d_{t})}{\partial d_{t}} \frac{\partial d_{t}}{\partial {m}_{t}} \\ & + \left[\frac{\partial {m}_{t+1}}{\partial {m}_{t}} + \frac{\partial {m}_{t+1}}{\partial c_{t}} \frac{\partial c_{t}}{\partial {m}_{t}} + \frac{\partial {m}_{t+1}}{\partial d_{t}} \frac{\partial d_{t}}{\partial {m}_{t}} \right] \beta \vFunc^{{m}}_{t+1} + \beta \vFunc^{d}_{t+1} \frac{\partial d_{t}}{\partial {m}_{t}} \end{aligned}

but the Envelope theorem tells us to ignore all the terms that involve ct/mt\partial c_{t}/\partial {m}_{t} or dt/mt\partial d_{t}/\partial {m}_{t}; then because the only term in that whole mess above that does not involve either ct/mt\partial c_{t}/\partial {m}_{t} or dt/mt\partial d_{t}/\partial {m}_{t} is mt+1/mt=R\partial {m}_{t+1}/\partial {m}_{t} = \Rfree we have:

vtm=Rβvt+1m\vFunc_{t}^{{m}} = \Rfree \beta \vFunc_{t+1}^{{m}}

Applying the same Envelope theorem logic for dt1d_{t-1} yields:[1]

vtd=R(1δ)βvt+1m=(1δ)Rβvt+1m=(1δ)vtm\begin{aligned} \vFunc_{t}^{d} & = \Rfree(1-\delta) \beta \vFunc^{{m}}_{t+1} \\ & = (1-\delta) \Rfree \beta \vFunc_{t+1}^{{m}} \\ & = (1-\delta) \vFunc^{{m}}_{t} \end{aligned}

Think now about the case where depreciation is 100 percent (δ=1\delta=1); from (12) it is clear that in this case vtd=0\vFunc_{t}^{d} = 0. This makes sense because in this case the “durable” good is really a totally nondurable good. vtdt1=0\vFunc^{d_{t-1}}_{t} = 0 because the amount that you consumed of a nondurable good last period has no direct effect on your current utility (we have assumed that utility is time separable).

The δ=0\delta= 0 case is more interesting. In this case the marginal utility of having an extra unit of durable good last period is equal to the marginal utility of having an extra unit of wealth this period. Why? Because if δ=0\delta=0 the durable good doesn’t depreciate at all. How much would it cost to buy another unit of durable good today? One unit of wealth. Because the durable does not depreciate from period to period and can be transformed into and out of wealth at a one-to-one price, it is exactly as valuable as a unit of wealth.

Now we want to try to derive a relationship between the contemporaneous marginal utilities of dd and cc. From (9) we have:

utd=Rβvt+1mβvt+1d.\uFunc^{d}_{t} = \Rfree \beta \vFunc^{{m}}_{t+1} - \beta \vFunc^{d}_{t+1}.

and Rβvt+1m=utc\Rfree \beta \vFunc^{{m}}_{t+1} = \uFunc^{c}_{t} and from (12) vt+1d=(1δ)vt+1m\vFunc_{t+1}^{d} = (1-\delta) \vFunc^{{m}}_{t+1}. Substituting these into (13):

utd=utcβ(1δ)vt+1m=utc(1δ)RRβvt+1m=[1(1δ)R]utc=[r+δR]utc\begin{aligned} \uFunc_{t}^{d} & = \uFunc_{t}^{c}-\beta(1-\delta) \vFunc_{t+1}^{{m}} \\ & = \uFunc_{t}^{c} - \frac{(1-\delta)}{\Rfree} \Rfree\beta \vFunc_{t+1}^{{m}} \\ & = \left[1-\frac{(1-\delta)}{\Rfree}\right] \uFunc_{t}^{c} \\ & = \left[\frac{\rfree + \delta}{\Rfree}\right] \uFunc_{t}^{c} \end{aligned}

Assuming δ<1\delta<1, this equation tells us that the marginal utility in the current period of a unit of spending on the durable good is lower than the marginal utility of spending on the nondurable. Why? Because the durable good will yield utility in the future as well as in the present. What should be equated to the marginal utility of nondurables consumption is the total discounted lifetime utility from an extra unit of the durable good, not simply the marginal utility it yields right now. You don’t buy a car because it is worth $20,000 to you on the day you buy it; you buy a car because its expected discounted value over its lifetime is $20,000 or more.

Now assume the utility function is of the Cobb-Douglas form: u(c,d)=(c1αdα)1ρ1ρ.\uFunc(c,d)=\frac{({c^{1-\alpha }d^{\alpha })}^{1-\rho }}{1-\rho }. This implies that the instantaneous marginal utilities with respect to cc and dd are:

uc=(c1αdα)ρ(1α)cαdα=(c1αdα)ρ(1α)(d/c)αud=(c1αdα)ραc1αdα1=(c1αdα)ρα(d/c)α1\begin{aligned} \uFunc^{c} & = (c^{1-\alpha}d^{\alpha})^{-\rho} (1-\alpha)c^{-\alpha}d^{\alpha} \\ & = (c^{1-\alpha}d^{\alpha})^{-\rho} (1-\alpha)(d/c)^{\alpha} \\ \uFunc^{d} & = (c^{1-\alpha}d^{\alpha})^{-\rho} \alpha c^{1-\alpha} d^{\alpha-1} \\ & = (c^{1-\alpha}d^{\alpha})^{-\rho} \alpha (d/c)^{\alpha-1} \end{aligned}

Substituting these definitions into (14) gives:

(c1αdα)ρα(d/c)α1=(c1αdα)ρ(1α)(d/c)α(r+δR)α1α=(d/c)(r+δR)d/c=(α1α)(Rr+δ)γ\begin{aligned} (c^{1-\alpha}d^{\alpha})^{-\rho} \alpha (d/c)^{\alpha-1}& = (c^{1-\alpha}d^{\alpha})^{-\rho} (1-\alpha) (d/c)^{\alpha}\left(\frac{\rfree+\delta}{\Rfree}\right) \\ \frac{\alpha}{1-\alpha} & = (d/c)\left(\frac{\rfree+\delta}{\Rfree}\right) \\ d/c & = \left(\frac{\alpha}{1-\alpha}\right)\left( \frac{\Rfree}{\rfree+\delta} \right)\equiv \gamma \end{aligned}

What this implies is that whenever the level of nondurables consumption changes, the level of the stock of durables should change by the same proportion. Because expenditures on durable goods are equal to the change in the stock plus depreciation, a change in cc implies spending on durables large enough to immediately adjust the stock to the new target level. (Recall that dtd_{t} was the stock of durable good owned in period tt, while spending on the durable good was defined as xt=dt(1δ)dt1{x}_{t} = d_{t} - (1-\delta) d_{t-1}.)

Define γ=dt/ct\gamma = d_{t}/c_{t} as in (16). Now consider a consumer who had consumed the same amount of the nondurable good for periods ct2=ct1c_{t-2} = c_{t-1} but who between period t1t-1 and period tt learns some good news about permanent income; she adjusts her nondurables consumption up so that ct/ct1=(1+ϵt)c_{t}/c_{t-1} = (1+\epsilon_{t}). This implies that the level of spending in period tt is:

xt=dt(1δ)dt1=γ[ct(1δ)ct1]xt1=γ[ct1(1δ)ct2]=γδct1xt/xt1=γ[ct1(1+ϵt)(1δ)ct1]/γδct1=ϵt+δδ\begin{aligned} {x}_{t} & = d_{t} - (1-\delta) d_{t-1} = \gamma [c_{t} - (1-\delta) c_{t-1}]\\ {x}_{t-1} & = \gamma [c_{t-1} - (1-\delta) c_{t-2}] \\ & = \gamma \delta c_{t-1} \\ {x}_{t}/{x}_{t-1} & = \gamma[c_{t-1}(1+\epsilon_{t}) - (1-\delta)c_{t-1}]/ \gamma \delta c_{t-1} \\ & = \frac{\epsilon_{t} + \delta}{\delta} \end{aligned}

Assuming δ<1\delta < 1, this equation implies that spending on durable goods should be more variable than spending on nondurable goods. For goods with a low depreciation rate, spending should be much more variable. This is true because the ratio of the stock of durables to income is much larger than the ratio of the average level of spending on durables to income. Consider housing: a house might be worth 3 times permanent income, so fluctuations in permanent income mean perpetually buying new “chunks” of house (when PP rises) or selling off portions (when PP falls). This model abstracts from transactions costs, which are important in reality; durables spending is in fact empirically much more volatile than nondurables spending.

A further implication of this model is that the degree of correlation between nondurables spending growth and durables spending growth depends on the frequency under consideration. For a given quarterly depreciation rate (say, 5 percent per quarter), the durable good will have almost completely depreciated over the course of 10 years = 40 quarters because 0.9540=0.120.95^{40}=0.12. According to the model, over an interval long enough for the durable to have completely depreciated, the rate of growth of spending on the durable should match the rate of growth of spending of the nondurable, because over such a long interval they are really both nondurable.

Some evidence on this proposition is provided in the Jupyter notebook available here.

Footnotes
  1. Both here and in (10), the derivative vtd\vFunc^{d}_{t} should be understood as a differentiation with respect to dt1d_{t-1}.